![If [math]A[/math] and [math]B[/math] are two invertible matrices of the same order, then how can I prove that [math](AB)^{-1}=B^{-1}A^{-1}[/math]? - Quora If [math]A[/math] and [math]B[/math] are two invertible matrices of the same order, then how can I prove that [math](AB)^{-1}=B^{-1}A^{-1}[/math]? - Quora](https://qph.cf2.quoracdn.net/main-qimg-da6ca456a38e948908176db1128d33ea.webp)
If [math]A[/math] and [math]B[/math] are two invertible matrices of the same order, then how can I prove that [math](AB)^{-1}=B^{-1}A^{-1}[/math]? - Quora
![linear algebra - Why can all invertible matrices be row reduced to the identity matrix? - Mathematics Stack Exchange linear algebra - Why can all invertible matrices be row reduced to the identity matrix? - Mathematics Stack Exchange](https://i.stack.imgur.com/tPcoh.png)
linear algebra - Why can all invertible matrices be row reduced to the identity matrix? - Mathematics Stack Exchange
![SOLVED: Our definition of an invertible matrix requires that A be a square n x n matrix. Let's examine what happens when A is not square. For instance, suppose that B = [ SOLVED: Our definition of an invertible matrix requires that A be a square n x n matrix. Let's examine what happens when A is not square. For instance, suppose that B = [](https://cdn.numerade.com/ask_images/fc32869799a34ffc9965f00bdbbdbc5c.jpg)